If x 2 = 7 x + 5 , then we can write x 3 as a x + b . Find the value of a + b .
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That is very difficult to follow. Clarification on your solution would be greatly appreciated.
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Sorry, I combined a few steps for sake of brevity. Given that x 2 = 7 x + 5 , we then have that
x ∗ x 2 = x ∗ ( 7 x + 5 ) ⟹ x 3 = 7 x 2 + 5 x .
Now substitute x 2 = 7 x + 5 to find that
x 3 = 7 ∗ ( 7 x + 5 ) + 5 x ⟹ x 3 = 4 9 x + 3 5 + 5 x = 5 4 x + 3 5 ,
from which we have that a = 5 4 and b = 3 5 .
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Multiplying the given equation through by x gives us that
x 3 = 7 x 2 + 5 x = 7 ( 7 x + 5 ) + 5 x = 5 4 x + 3 5 ⟹ a + b = 5 4 + 3 5 = 8 9 .