I don't think it was in my course book!-III

Classical Mechanics Level 3

Find the speed at which the mass of an electron is double of its rest mass.

Assume that the mass of electron equals to 9.1 × 1 0 − 31 kg 9.1 \times 10^{-31} \text{kg} , c = 3 × 1 0 8 m/s c = 3 \times 10^8 \text{ m/s} .

Hint: Use the equation for relativistic mass given by Lorentz transformation.

A problem from Special Theory of Relativity


The answer is 2.598E+8.

Swapnil Das by Swapnil Das , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Ansh Bhatt
May 13, 2015

7 Helpful 0 Interesting 0 Brilliant 0 Confused

Excellently written!

Swapnil Das - 6 years, 1 month ago

Shouldnt it be 1-(-1/2) or 1+1/2 during those last couple steps? Getting 5/4 on the RHS in the end instead of 3/4?

Sandro Flo - 5 years, 6 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...