I forgot my radii! 2

Geometry Level 1

I have two spheres with different sizes. The radius of the larger sphere is R R and the radius of the smaller sphere is r r . Given that the volume of the larger sphere is twice the volume of the smaller sphere, find the value of R r \dfrac Rr .

I forgot my radii!

Cannot be determined 2 3 \sqrt[3]{2} 2 \sqrt{2} 2

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1 solution

Ethan Mandelez
Dec 5, 2020

The volume of a sphere is 4 3 π a 3 \frac{4}{3}πa^3 , where a a is the radius. From the information given above:

2 × 4 3 π r 3 = 4 3 π R 3 2\times\frac{4}{3}πr^3 = \frac{4}{3}πR^3

8 3 π r 3 = 4 3 π R 3 \frac{8}{3}πr^3 = \frac{4}{3}πR^3

( R 3 r 3 ) = 2 \left(\dfrac {R^3}{r^3} \right) = 2

Hence ( R r ) = 2 3 \left(\dfrac {R}{r} \right) = \boxed{\sqrt[3]{2}}

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