I have 2 circles with different sizes. All I know is that:
The sum of the areas is 5 8 π
The sum of the circumferences is 2 0 π
If the radii of the two circles are a and b respectively, submit your answer as a + b .
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Really nice, well done! Guess this is the 'apple way 🍎🍏' to do it 👍
There are several methods to do this, here is the solution using simultaneous equations:
Very nice write-up. Just one comment on a different way to solve the equations: once you get to a 2 + b 2 = 5 8 and a + b = 1 0 you can square the second one to get a 2 + 2 a b + b 2 = 1 0 0
From here, 2 a b = 1 0 0 − 5 8 = 4 2 , and a 2 − 2 a b + b 2 ( a − b ) 2 = 1 6 = 5 8 − 4 2
By symmetry, we can assume a > b ; so a − b = 4
Combining this with a + b = 1 0 gives the values of a and b .
I just mention this because this exact technique is used in solving cubic equations, and it's a useful trick to know.
Thanks for your comment, what a nice way to solve this problem! And this technique is very useful to solve more complex equations too. Again, thank you for the tip
"The sum of the circumferences is 2 0 π "
"If the radii of the two circles are a and b respectively, submit your answer as a + b "
The sum of the circumferences is 2 π ( a + b ) . I don't need to find the exact values of a or b to answer this question. I just need to take the sum you've given me and divide by 2 π .
Nice spot! I should have just asked for the radius of the smaller circle instead for the sum of the two....but anyways this is a very good shortcut to take, well done!
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Apple way 🍎🍏 2 π a + 2 π b = 2 0 π a + b = 1 0 No need for finding for a and b
EDIT
If you want to find a and b a 2 + b 2 = 5 8
( a + b ) 2 − 2 a b = 5 8
4 a b = 8 4 ( a − b ) = ± ( a + b ) 2 − 4 a b ⟹ ( a − b ) = ± 4 Solving for a and b a = 7 o r 3 , b = 7 o r 3