This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Note first that cos ( sin − 1 ( − 0 . 3 ) ) = cos ( − sin − 1 ( 0 . 3 ) ) = cos ( sin − 1 ( 0 . 3 ) ) .
Next, working from the middle of the expression outward, we then note that (i): sin ( sin − 1 ( y ) ) = y for − 1 ≤ y ≤ 1 . As y = cos ( sin − 1 ( 0 . 3 ) ) does lie in this interval, the given expression simplifies to
sin ( cos − 1 ( cos ( sin − 1 ( 0 . 3 ) ) ) .
Now cos − 1 ( cos ( y ) ) = y for 0 ≤ y ≤ π . Since y = sin − 1 ( 0 . 3 ) does lie in this interval, the expression further simplifies to
sin ( sin − 1 ( 0 . 3 ) ) = 0 . 3
due to statement (i) outlined above.