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Calculus Level 4

lim x 0 + ln ( ( sin x ) tan x ) = ? \large \displaystyle\lim_{x\to 0^+} \ln((\sin x)^{\tan x}) = \, ?

None of these choices -1 The limit does not exist 2 1 0 -2

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1 solution

Tom Engelsman
Dec 26, 2016

Let us write l n s i n ( x ) t a n ( x ) ln sin(x)^{tan(x)} as t a n ( x ) l n ( s i n ( x ) ) = l n ( s i n ( x ) ) c o t ( x ) . tan(x) \cdot ln(sin(x)) = \frac{ln(sin(x))}{cot(x)}. Applying L'Hopital's Rule twice results in:

l n ( s i n ( x ) ) c o t ( x ) c o t ( x ) c s c 2 ( x ) c s c 2 ( x ) ( 2 c s c ( x ) ) ( c s c ( x ) c o t ( x ) ) = 1 2 c o t ( x ) . \frac{ln(sin(x))}{cot(x)} \Rightarrow \frac{cot(x)}{-csc^2(x)} \Rightarrow \frac{-csc^2(x)}{(-2csc(x))(-csc(x)cot(x))} = -\frac{1}{2cot(x)}.

which the limit approaches zero as x 0. x \rightarrow 0.

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