Which of the following is a positive number?
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Firstly, sin x ° is positive if 0 ° < x ( m o d 3 6 0 ) < 1 8 0 ° . As 1 2 9 0 ° ( m o d 3 6 0 ) = 2 1 0 ° , sin 1 2 9 0 ° is negative.
Secondly, cot x ° is positive if tan x ° is positive, and this is positive if 0 ° < x ( m o d 1 8 0 ) < 9 0 ° , which is not the case here as 1 2 0 0 ° ( m o d 1 8 0 ) = 1 2 0 ° .
Thirdly, cos x ° is positive in the ranges 0 ° < x ( m o d 3 6 0 ) ≤ 9 0 ° and 2 7 0 ° < x ( m o d 3 6 0 ) ≤ 3 6 0 ° , but 5 7 0 ° ( m o d 3 6 0 ) = 2 1 0 ° and is therefore negative.
This leaves us with tan 9 6 0 ° as the answer, but for the record, 9 6 0 ° ( m o d 1 8 0 ) = 6 0 ° and is therefore positive.
We know that sin is positive in I and II quadrants, cos in I and IV quadrants and tan (and hence cot) in I and III quadrants. Also, we can 'reduce' the angles greater than 360 deg to fall within the principal range (0 to 360 deg) by dividing the given measure by 360 and taking its remainder as the new angle. In the choices given with the question, only tan 960 deg is positive because 960/360=(2*360)+240 which means that tan 960=tan 240 and as we know that 240 deg falls in the III quadrant, the tan function of any such angle is also positive.
You should also show how the other choices lead to a negative value.
Take out 360 as many as possible and then see the remaining number and use the following parameter,
So in case 1 that is 1290, Take out as many 360 as possible and the remaining digit that is left is 210 that lies in 3rd quadrant where only Tangent is positive so it will be negative,
In case 2 the left over digit is 240 that again is in 3rd Quadrant where Tangent is the only positive function so it'll be positive and hence you reached the anwser in 2nd option
Convert all to 0<x<360. tan960 = tan 240 (+ve)
Ideally, you should state that the tangent of an angle in the third quadrant is positive. And you should show that the other answer choices yields a negative value.
For a fraction to be positive, the numerator and denominator must be either both positive or negative. By the ASTC rule (Quadrant I - everything is positive; Quadrant II: Sine is positive; Quadrant III: Tan is positive; Quadrant IV: Cosine is positive), it can be seen that in quadrants II and IV, one of sin or cosine is positive, while the other is negative. This would yield a negative sine value, which is sin/cos. Another way to think about this would be in the case of a unit circle, in which case the sin value can be shown as the y-value while the cos value can be shown as the x-value. In the first quadrant, {x, y} will both be positive. In the second, x would be negative while y would still be positive - hence why sin is positive in the second quadrant (ASTC rule once again). In the third quadrant, x and y are both negative, leading to negative sine and cosine values, resulting in a positive tangent value. As for the fourth quadrant, the x value would be positive while y, negative, hence a positive cosine value and negative sine value!
All functions are positive in the first quadrant; Only Sin functions are positive in the second quadrant; Tan functions are positive in the third quadrant and Cos functions are positive in the fourth quadrant... 960 will lie in the third quadrant where only tan is positive...
All Students Take Calculus! All, Sine, Tangent, Cosine - Which function(s) is/are positive in all four quadrants, including their reciprocals.
tan 960 = tan 240 which is between 180 and 270 and thus positive.
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Rule of 360 degrees: