The average human heart pumps 5 L/min of blood through the human body at a pressure of 1 0 4 Pa . For a person who lives 80 years, what is the total energy output of his heart in Joules ?
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Both the age of the person and the pumping rate are only known to 1 significant figure.
Too many significant figures in solution, only one significant figure given in question and answer should be rounded.
Please remember that someone looking at your response is trying to learn. Give an equation. FxD=PxV, and provide no units for the terms, and then say: Hence and jump to work per second means the student has to go study all the definitions to follow your logic. The multiplication is easy, but will give you the wrong answer if you do not know unit relationships. I agree it is harder to write up, but you should assume the person looking at your answer missed something you think is trivial.
What was incredibly frustrating and unclear for me that you should mention is where the 10^-3 comes from. Since Joules is in N * m units and pascals are in N / m^2 units I assume you are multiplying the 10^4 pascals by (m^3) to match up units? I'm still not totally sure how you came about that number
Regards the 10E-3, that is there to turn litres (1000ml) into m^3. The conversion is 1 litre = 0.1m* 0.1m*0.1m = 0.001 m^2. So your heart beats 0.005 m^3 of blood per minute (approximately 1metric tonne every 3hr 20min).
The force * distance = volume * pressure is really cool and best understood from units.
Newtons * meters = joules (definition)
Volume (metres^3) * pressure (newtons/m^2) = (newtons * m^3)/m^2=newtons*metres=joules
Sometimes maths trumps intuition.
All of the solutions assume the inlet pressure to the heart is 0 and heart has to generate 10^4 Pa pressure. The actual work done is based on pressure difference between inlet and outlet of heart.
Will someone please, please, please explain to me why my answer continues to be off by a power of 10? The procedure I used is as follows, just based on unit conversions (without using said formula F d=p V; I didn't know it existed).
5 L/min = (5 kg / min) * (1 m^3 / 1000 kg) = 0.005 m^3 / min. (0.005 m^3 / min) * (60 min / 1 hr) * (24 hrs / 1 day) * (365.25 days / 1 year) * (80 yrs) = 210384 m^3. (210384 m^3) * (10E4 kg / m s^2) = 2.104E10 kg m^2 / s^2 = 2.104E10 J.
Why doesn't this work?
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1 Pa is 1 N / m^2 not 1 kg / m^2. And there is your factor of 10
The heart is not a pump.
I got the force with pressure and volume (p=F/S. => F=S p), but where does the displacement/distance come in or where should I take it,(E=A=F s?) I understand I got the force used in 80 years but force and work are not the same?
Work done = Pressure x Volume
Hence, Work done/min = Pressure x Volume/min
= 1 0 4 P a x 1 0 0 0 0 0 0 5 0 0 0 m 3 / m i n
= 5 0 J / m i n
= 3 0 0 0 J / h o u r
= 7 2 0 0 0 J / d a y
= 2 6 2 9 8 0 0 0 J / y e a r
= 2 1 0 3 8 4 0 0 0 0 J / 8 0 y e a r s
Strictly J/80 years is a power and not energy. Best to convert the l/minute to cubic metres per second - which is then in SI consistent units. Then just multiply all the numbers together. Simples - That is the point of SI.
What to write in text box?
Too many significant figures in solution, only one significant figure given in question and answer should be rounded.
Using dimensional analysis, we know that P a = m 2 N ( P = A F ) and that 1 L = 1 0 0 0 m 3 . Then, we see that P a ⋅ L = N ⋅ m = J . Thus, the heart's energy output is 1 0 0 0 5 ⋅ 1 0 4 = 5 0 J per minute. Converting to 80 years yields: 5 0 × 6 0 × 2 4 × 3 6 5 . 2 5 × 8 0 = 2 . 1 0 4 × 1 0 9
Too many significant figures in solution, only one significant figure given in question and answer should be rounded.
Let the surface area of the blood vessel (which we consider to be uniform throughout) be A.
V = Ad (Volume = A * distance) F = pA (Force = pressure * A) W = Fd = (pA)(V/A) = pV = pRt (where R is the flow rate).
Substituting, W = 1 0 4 × ( 5 × 6 0 × 2 4 × 3 6 5 . 2 5 × 8 0 ) / 1 0 0 0 = 2 1 0 3 8 4 0 0 0 0
Firstly, we are given 2 important dats : change in volume and pressure. Hence from the equation
W=PdV
We can find the work done per second by plugging in the values for P and dV but we have to change 5L/min into cubic metres per second.
From W=PdV , W= 1 0 4 × 8 . 3 3 3 − 5
W=0.8333J
So the total energy output of their heart in Joules is 8 0 × 3 6 5 . 2 5 × 2 4 × 3 6 0 0 × 0 . 8 3 3 3
= 2 . 1 0 9 Joules
oh mistake, should be 2 . 1 0 × 1 0 0 9
The solution comes out of the units. You want an answer in Joules, and a Joule is a Newton metre. You are given Pascals, and a Pascal is a Newton per metre cubed. You are also given litres, i.e. decimetres cubed, so you just need to flip that into metres cubed by X 10 E-3, then you can see that you just need to multiply pressure by flow and scale up from one minute to the lifetime.
J=Nm Pa=N/m2 J=m3*Pa;compute lifetime volume & multiply by E4 Pa.
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Energy output is equal to work done which in turn is equal to
F o r c e × D i s p l a c e m e n t = P r e s s u r e × V o l u m e
Hence, work done per second is:
w = 1 0 4 × 5 × 6 0 1 0 − 3 = 6 5 W a t t s
Hence, the energy output in 8 0 years is:
E = 6 5 × 8 0 × 3 6 5 . 2 5 × 2 4 × 3 6 0 0 = 2 . 1 0 3 8 × 1 0 9 J