I Know What You Are, But What Is Y?

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$\quad \quad \quad \frac { 4y }{ \sqrt { 2\alpha } } =6{ \alpha }^{ 2 }\\ \\ If\quad \alpha =2,\quad what\quad is\quad y?$

144 12 48 24 4

1 solution

Maddie Anderson
Apr 13, 2015

First things first, we need to input 2 where $\alpha$ is now.

Therefore, $\sqrt { 2 \alpha }$ becomes $\sqrt { 4 }$ , which is equal to 2. Next, input 2 into $6\alpha ^{ 2 }$ . Be sure to take the square of $\alpha$ before you multiply $\alpha$ by 6, because PEMDAS states that we do exponents before multiplication. Done correctly, $6\alpha ^{ 2 }$ equals 24.

Done incorrectly(multiplication first) it can equal 144. Big difference, am I right? Anyway, our equation becomes $\frac { 4y }{ 2 } =24$ . We can multiply both sides by 2, so that we get $4y=48$ .

48 divided by 4 is 12, so we get $y=12$ . Ta-da! :D

I Know What You Are, But What Is Y?

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