I love this problem.

Algebra Level 2

Evaluate:

9 x − 7 i > 3 ( 3 x − 7 u ) 9x - 7i > 3(3x-7u)

Note that ' i i ' is a variable, not 'imaginary'...

i ≤ 3 u i \leq 3u i > 3 u i > 3u i < 3 u i < 3u i ≥ 3 u i \geq 3u

Jeremy Bansil by Jeremy Bansil , 27, Philippines

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1 solution

Jeremy Bansil
Jul 27, 2014

9 x − 7 i > 3 ( 3 x − 7 u ) 9x - 7i > 3(3x - 7u) Distribute.

9 x − 7 i > ( 3 ) ( 3 x ) − ( 3 ) ( 7 u ) 9x - 7i > (3)(3x) - (3)(7u) Multiply.

9 x − 7 i > 9 x − 21 u 9x - 7i > 9x -21u Cancel by adding − 9 x -9x .

− 7 i > − 21 u -7i > -21u Cancel by dividing by − 7 -7 (and automatically changing the 'greater than' sign)

And finally...

i < 3 u \boxed{i <3u}

4 Helpful 0 Interesting 0 Brilliant 0 Confused

Why do you love it so much? No offense, but it isn't something most of us haven't seen before ...

Ayo Osilaja - 6 years, 10 months ago

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Technically I don't love this problem. I'm just giving a clue to the people that the answer is i < 3 u i < 3u which looks like 'I love you' (in which <3 looks like a heart)

Jeremy Bansil - 6 years, 10 months ago

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Quite an old one, guessed it the moment I saw i , u , and the inequality !!!

Shaurya Chats - 6 years, 10 months ago

This is the problem almost everyone gets wrong. I love this problem too along with many more :D

Kevin Mo - 6 years, 10 months ago

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