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Let G be a planar graph with V vertices such that each vertex has degree exactly 5. What is the least possible value of V?


The answer is 12.

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1 solution

Alex Wang
Nov 3, 2014

The total degree of G is 5V since each vertex has a degree of 5. Each edge contributes two vertices, so we know 2E=5V.

For any planar graph, E 3 V 6 E \leq 3V-6 . Plugging in what we have for E, we can simplify the inequality to become V 12 V \geq 12 .

Now, our task is to figure out if there is a graph with 12 vertices and with each vertex degree 5. Although it's painful, there is indeed a graph (vertex-edge skeleton of an icosahedron).

Therefore, our answer is 12 \boxed{12} .

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