An algebra problem by Akhil Bansal

Algebra Level 1

5 × 5 + 5 / 5 5 = ? \large 5 \times 5 + 5 / 5 - 5 = \ ?

1 10 21 45 2 5 0 22

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4 solutions

Don't worry, there's no tricks, just use BODMAS technique. No, it's trolling you:

5 × 5 + 5 ÷ 5 5 5\times 5+5 \div5-5 = 25 + 1 5 = 25+1-5 = 21 = \boxed{\color{#D61F06}{21}}

So here is a troll for you , here , there should be DIMAS not BODMAS .

karandeep singh ludhar - 5 years, 9 months ago
Akhil Bansal
Sep 1, 2015

Given expression: 5 × 5 + 5 / 5 5 5 \times 5 + 5 / 5 - 5 .
Applying B O D M A S BODMAS ,

[ { ( 5 × 5 ) + ( 5 / 5 ) } 5 ] \Rightarrow [\{(5 \times 5) + (5 / 5)\} - 5 ] 25 + 1 5 \Rightarrow 25 + 1 - 5 21 \Rightarrow \color{#0C6AC7}{ \boxed{21}}

Good solution!!!

S.k. Bansal - 5 years, 9 months ago

Akhil bro, still 88% solvers! XD XD

Swapnil Das - 5 years, 9 months ago
Zackchan Fox
Sep 2, 2015

Adam Phúc Nguyễn is right but I use the bomdas technique can really work Bracket Of Multiply Divide Addition Subtraction So I say 21 and I am actually in jamaica

I am also in Jamaica. I say BOMDAS is a simple solution.

Clyve Bowen - 5 years, 9 months ago
Charity Aghahowa
Sep 1, 2015

Use BOMDAS, Brackets Over, Multiplication, Division, Addition & Subtraction.

5 x 5 + 5 ÷ 5 - 5

= 25 + 5 ÷ 5 - 5

= 25 + 1 - 5

= 26 - 5

= 21

Pretty straight forward once you understand the BOMDAS rule.

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