I want my money and i want it now !!!!!!

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A total amount of money of 4800 4800 dollars has to be divided among a number of employees which is unknown such that each of them receives an equal amount of money.If three employees give up on their cut from the money ,then each of the remaining employees would receive 80 80 dollars more.Find the total number of employees since the very beginning.


The answer is 15.

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1 solution

Prasun Biswas
Feb 7, 2014

Let us take the number of employees at the beginning as n n and their original share of the money as x x . So, from the question, we get ----

x = 4800 n n x = 4800 x=\frac{4800}{n} \implies nx=4800 .....(i) and,

x + 80 = 4800 n 3 x+80=\frac{4800}{n-3}

n x + 80 n 3 x 240 = 4800 4800 + 80 n 3 x 240 = 4800 [From (i)] 80 n 3 x 240 = 0 \implies nx+80n-3x-240=4800 \implies 4800+80n-3x-240=4800 \text{[From (i)]} \implies 80n-3x-240=0 .....(ii)

Putting value of x = 4800 n x=\frac{4800}{n} from (i) in equation (ii), we get ------

80 n 3 ( 4800 n ) 240 = 0 80n-3(\frac{4800}{n})-240=0

80 n 3 ( 4800 n ) = 240 \implies 80n-3(\frac{4800}{n})=240

80 n 2 14400 n = 240 80 n 2 14400 = 240 n \implies \frac{80n^2-14400}{n}=240 \implies 80n^2-14400=240n

80 n 2 240 n 14400 = 0 \implies 80n^2-240n-14400=0

n 2 3 n 180 = 0 ( n 15 ) ( n + 12 ) = 0 n = 15 [Neglecting n+12=0, n=(-12) as n cannot be (-ve) \implies n^2-3n-180=0 \implies (n-15)(n+12)=0 \implies n=\boxed{15}\text{ [Neglecting n+12=0, n=(-12) as n cannot be (-ve)}

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