I want to see more of this constant

lim n ( p n 1 p ln ( ln ( n ) ) ) \Large \lim_{n \to \infty} \left( \sum_{p\leq n}\frac{1}{p}-\ln(\ln(n))\right)

If the above limit equals M M , find 100 M \lfloor100M \rfloor .

Clarification : The sum is over all primes less than or equal to n n .


The answer is 26.

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1 solution

Mark Hennings
Jan 21, 2016

M M is the Meissel-Mertens constant: M = 0.2614972128476427837554268386086958590516... M \,=\, 0.2614972128476427837554268386086958590516... . This result is the formula that defines M M . Without reproducing Merten's Second Theorem, there is nothing more to prove.

On the other hand, the result is interesting, since it is a stepping-stone to the Prime Number Theorem.

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