I Was Vey Amaze At The Solution 15

Geometry Level 3

Suppose we have a square A B C D ABCD whose side is 2018 2018 units. The points S S and T T are located at side B C \overline{BC} such that, B S = 1009 \overline{BS} = 1009 units, T S = 336 1 3 \overline{TS} = 336 \dfrac{1}{3} units and point T T can be found in segment B S \overline{BS} . Solve for the sum:

B A S + B A T \angle BAS + \angle BAT


Note: The angles are in degrees.


For more problems like this, try this set .


The answer is 45.

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