I wonder which problem?

A recent problem I posted had the following properties:

  • A sixth of all viewers got the answer correct
  • A quarter of all people who attempted got the answer correct

If the fraction of the number of people who attempted to the number of people that viewed can be represented as a b \dfrac {a}{b} , where a a and b b are coprime positive integers, what is a + b a+b ?


The answer is 5.

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1 solution

Sharky Kesa
Sep 10, 2016

Let x x be the number of viewers and y y be the number of people who attempted. Thus

x 6 = y 4 4 6 = y x y x = 2 3 \begin{aligned} \dfrac {x}{6} &= \dfrac {y}{4}\\ \implies \dfrac {4}{6} &= \dfrac {y}{x}\\ \implies \dfrac {y}{x} &= \dfrac {2}{3} \end{aligned}

Thus, 2 3 \frac{2}{3} of all people who viewed attempted the problem.

BTW, the problem was this .

well it should be a logic problem

Ayush G Rai - 4 years, 9 months ago

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It's number theory technically.

Sharky Kesa - 4 years, 9 months ago

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ya Thats true!

Ayush G Rai - 4 years, 9 months ago

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