Ideal Gas Law Problem 1

Chemistry Level 2

A container has a volume of $1000 \text{ m}^3$ and allows the pressure to be $5\times10^6 \text{ Pa}$ . What is the maximum mass of hydrogen gas the container can store (in kilograms) at $25^\circ \text{C}$ ?

Assume that hydrogen is an ideal gas.

$M_r(\ce{H2})=2$

You may refer to Chemistry - Ideal Gas .

2.02\times10^3 \text{ kg}

4.04\times10^3 \text{ kg}

4.81\times10^4 \text{ kg}

0.04\times10^6 \text{ kg}

2 solutions

Tibrôncio Cavalcante
Mar 12, 2017

Given:

V= 1000 m^3 => 10^6 L

P = 5,0×10^6 Pa => (9,87×10^-6) 49,35 atm

MM= 2,0 g/mol

R= 0,082 atm.L/mol.K

PV = nRT :. n=m/MM

PV = m/MM RT

m = PVMM/RT :.

m = 49,35 atm× 10^6 L × 2,0 g/mol ÷ 0,082 atm.L/mol.K × 298 K

m = 4,039 × 10^6 g -> 4,039 × 10^3 kg.

Deepak Sharma
Feb 5, 2014

$P=5\times10^6 Pa$ ; $V=10^3 m^3$ ; T=298 K; $R=8.314 JK^{-1}mol^{-1}$ ; $M_{r}=2\times10^{-3} kg$ Therefore, using ideal gas equation PV=nRT, number of moles n= $\frac{PV}{RT} =\frac{5\times10^9}{8.314\times298}$ So $n=2.02\times10^6$ moles. Thus mass of hydrogen stored in the container= $n\times M_{r} = 4.04\times10^3$

forgot to convert 2g/mol into kg/mol

Laurence Uy - 6 years, 11 months ago

$1~Pa = 1~Nm^{-2}~and~T = 298.16 K$

Lu Chee Ket - 5 years, 3 months ago

Ideal Gas Law Problem 1

You may refer to Chemistry - Ideal Gas .

2 solutions

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