Identify the graph - 2

Calculus Level 3

The graph of

1 x + 1 y = 2 \dfrac{1}{x} + \dfrac{1}{y} = 2

is a hyperbola . Where is its center ?

( 1 2 , 1 2 ) (-\frac{1}{2}, -\frac{1}{2} ) ( 1 , 1 ) (-1,-1) ( 1 , 1 ) (1, 1) ( 1 2 , 1 2 ) (\frac{1}{2}, \frac{1}{2})

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2 solutions

Chris Lewis
Sep 6, 2020

As x ± x \to \pm \infty , y 1 2 y \to \frac12 ; as y ± y \to \pm \infty , x 1 2 x \to \frac12 .

These asymptotes intersect at the hyperbola's centre, ( 1 2 , 1 2 ) \boxed{\left(\frac12,\frac12\right)} .

Tom Engelsman
Sep 12, 2020

Solving for y y in terms of x x yields y = 1 2 + 0.5 2 x 1 y = \frac{1}{2} + \frac{0.5}{2x-1} , which has a vertical asymptote at x = 1 2 x = \frac{1}{2} and a horizontal asymptote at y = 1 2 . y = \frac{1}{2}. Thus the hyperbola's center is the intersection of these two asymptotes: ( 1 2 , 1 2 ) . \boxed{(\frac{1}{2}, \frac{1}{2})}.

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