Identifying a sphere

Geometry Level pending

You are given three points in the Cartesian 3D space: A ( 0 , 0 , 4 ) , B ( 5 , 0 , 6 ) , C ( 7 , 7 , 10 ) A (0, 0, 4), B(5, 0, 6), C(7, 7, 10) , and you are asked to construct a sphere that passes through A , B , C A , B, C , and at the same time be tangent to the x y xy plane. There are two spheres that satisfy these requirements. Select the smaller one and let its radius be R R . Enter 1 0 4 R \lfloor 10^4 R \rfloor as your answer.


The answer is 63751.

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1 solution

Steven Chase
Mar 2, 2021

The center of the sphere is at ( x 0 , y 0 , R ) (x_0, y_0, R) . All three of these numbers are unknown. Solve the following system of nonlinear equations for these values. Newton Raphson works well here.

( A x x 0 ) 2 + ( A y y 0 ) 2 + ( A z R ) 2 = R 2 ( B x x 0 ) 2 + ( B y y 0 ) 2 + ( B z R ) 2 = R 2 ( C x x 0 ) 2 + ( C y y 0 ) 2 + ( C z R ) 2 = R 2 (A_x - x_0)^2 + (A_y - y_0)^2 + (A_z - R)^2 = R^2 \\ (B_x - x_0)^2 + (B_y - y_0)^2 + (B_z - R)^2 = R^2 \\ (C_x - x_0)^2 + (C_y - y_0)^2 + (C_z - R)^2 = R^2

Solution 1:

x 0 = 1.9499 y 0 = 5.5856 R = 6.3751 x_0 = 1.9499 \\ y_0 = 5.5856 \\ R = 6.3751

Solution 2:

x 0 = 13.9499 y 0 = 12.5856 R = 46.1248 x_0 = -13.9499 \\ y_0 = -12.5856 \\ R = 46.1248

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