Identify the term in place of ?
1 , 10 , 45 , 120 , 210 , ? , 210 , 120 , 45 , 10 , 1
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Its the coefficient of the pascal triangle in the 11th row.. (x+y)^10
superb solution
( 0 1 0 ) , ( 1 1 0 ) , ( 2 1 0 ) , . . . . . . , ( 9 1 0 ) , ( 1 0 1 0 )
So the desired number is ( 5 1 0 ) = 2 5 2
Rule: To get any number from the previous one: Multiply current number by (11 - current position) then divide by (current position) :
Here's how it works:
To get 2nd number: 1 X (11 - 1) / 1 = 10
To get 3rd number: 10 X (11 - 2) / 2 = 45
To get 4th number: 45 X (11 - 3) / 3 = 120
To get 5th number: 120 X (11 - 4) / 4 = 210
To get 6th number (the missing one) : 210 X (11 - 5) / 5 = 252
We can also continue and we'll get the same numbers in decreasing order:
To get 7th number: 252 X (11 - 6) / 6 = 210
To get 8th number: 210 X (11 - 7) / 7 = 120
To get 9th number: 120 X (11 - 8) / 8 = 45
To get 10th number: 45 X (11 - 9) / 9 = 10
And finally,
To get 11th number: 10 X (11 - 10) / 10 = 1
Here's how i did it
1 − 1 0 + 4 5 − 1 2 0 + 2 1 0 + 2 1 0 − 1 2 0 + 4 5 − 1 0 + 1
2 5 2
You got this correct because r = 0 ∑ n ( − 1 ) n ( r n ) = 0
210*6/5 = 252. Binomial expansion theorem aka Pascal's Triangle.
Note that these are binomial coefficients. In fact, they are of the form ( n 1 0 ) . The answer is ( 5 1 0 ) = 2 5 2 .
1x10/1=10_ 10x9/2=45_ 45x8/3=120_ 120x7/4=210_ 210x6/5=252
This is just the 11th row in Pascal's Triangle
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(10/1),(45/10=9/2),(120/45=8/3),(210/120=7/4),(x/210=6/5) therefore x=6*210/5=252