'If clear with functions' Part-2

If we graph the line given by $y=\dfrac{x}{100}$ and the curve $y=\sin(x)$ , the number of points they have in common is what we require.Here we have $x$ is measured in radians . Since $y=\dfrac{x}{100}$ , as value of $y$ exceeds $1$ , the line goes away from the sine curve and does not intersect.Let $x=k\pi$ for some real $k$ such that $\dfrac{k\pi}{100}=1 \Rightarrow k=\dfrac{100}{\pi} \approx \dfrac{700}{22} \approx 31.8$ . Since $31\pi < 31.8\pi < 32\pi$ , the last point that the line intersects lies on the part of curve that terminates on $31\pi$ . Thus the line intersects the curve at $31$ distinct points on right side of $Y$ axis. By symmetry , it also intersects the curve at $31$ distinct points on left side of $Y$ axis. Origin is also common point to the line and curve. And hence total points or total solutions $=31+31+1=63$ .