Stand up. Jump. When you jump you give yourself a velocity away from the earth. If you have a mass of 80 kg and can jump 1 m high, what is the magnitude of the velocity in m/s you imparted to the earth when you left the ground?
Details and assumptions
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
If you jump one meter high, then the initial velocity you had when leaving the ground can be found via
v f 2 = v i 2 + 2 a y → 0 = v i 2 + 2 ( − 9 . 8 ) ( 1 ) → v i = 4 . 4 2 7 m/s.
By momentum conservation we therefore have m e v e = − m i v i which allows us to solve for the velocity of the earth, v e = − 5 . 9 E − 2 3 m/s. Taking the magnitude gives us our answer.