If p,q,r are any real numbers, then which option is true?
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Consider m i n p , q (or min{p, q}) = 2 1 ( p + q − ∣ p − q ∣ ) . When p≥q, ∣ p − q ∣ = p − q , else ∣ p − q ∣ = q − p . Hence the right hand side of the given equation reduces to q (p≥q) or p (q>p) respectively. In both cases, the resulting value is the minimum of p and q. Hence this option is correct.
max{p, q}<max{p, q, r} is incorrect when p=2, q=3, r=1. That is, this option is not true for 'any' real numbers.
max{p, q}<min{p, q, r} is incorrect when p=1, q=2, r=3 (or for any case as max{p, q}≥min{p, q}≥min{p, q, r}).