IIT JEE Problem

Probability Level 3

The number of integers greater than 6000 that can be formed, using the digits 3, 5, 6, 7 and 8, without repetition, is:


The answer is 192.

Rajdeep Bharati by Rajdeep Bharati , 21, India

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1 solution

Rajdeep Bharati
Dec 19, 2015

Four digit numbers will start from 6, 7, 8

3 x 4 x 3 x 2 = 72

Five digit numbers = 5! = 120

Total number of integers = 192.

3 Helpful 0 Interesting 0 Brilliant 0 Confused

max no. digits in integers greater than 6000 are not specified here..!!

Soundarya Gupta - 5 years, 5 months ago

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It has been specified that we have to use the digits 3, 5, 6, 7 and 8; without repetition.

Rajdeep Bharati - 5 years, 5 months ago

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