I'll advise you to think twice!

A weightless rigid rod with a load at the end is hinged to a point on the wall, so that it can rotation in all directions.

The rod is kept in the horizontal position with the help of an inextensible thread of length l l , fixed at its midpoint. The load receives a momentum in the direction perpendicular to the plane of the figure. Determine the period T T , of the small oscillation of the system.

Let this be given by 2 π a l b g 2\pi \sqrt{\dfrac{al}{bg} } , where a a and b b are coprime positive integers. Find a + b a+b .


Not original.


The answer is 3.

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1 solution

Let us construct point B', which belongs to the line AB so that point B is the mid point of AB'. It is easily seen that when at rest the load and point B' are on the same vertical line. Besides that the whole line AB' will stay at rest when the rod keeps rotating and during this motion the load will always stay at costant distance 2l from the stationary point B'. Hence one gets SHM of a simple pendulum with the 2l length.

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