I'll always win!
There are 2 piles of pebbles, each pile contains 28 and 20 pebbles respectively, Dyson and Wayne will be taking pebbles from the piles. They can take as much pebbles ad they like, but it is restricted to not take any and take from both piles at the same time. The player who takes the last or last few pebbles wins. If Dyson goes first and then Wayne, and if both uses the best strategy, who will always win?
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1 solution
Firstly, Dyson takes 8 pebbles, making both piles 20. Then, if Wayne picked x pebbles from a pile, Dyson must always pick x pebbels from the other pile. After some rounds, Dyson will always get the last or few pebbles. Thus, Wayne will lose.