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Classical Mechanics Level 2

Find the magnitude of force required to hold a machine gun at same position, firing 100 bullets each of mass 10 gram 10 \text{ gram} with a velocity of 700 ms − 1 700 \text{ ms}^{-1} in 60 seconds.

If the answer is in the form A B newton \frac{A}{B} \text{ newton} .

Find A + B A+B , where A A and B B are positive co-prime integers.


The answer is 38.

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Akshat Sharda by Akshat Sharda , 21, India

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2 solutions

100 bullets of 10gm each = 1kg. So simply put, we are giving a 1kg mass a velocity of 700m/s in 60 sec. So rate of change of momentum is ((1×700)-(1×0))/60 which on simplification gives 35/3..... So the answer is 38.

3 Helpful 0 Interesting 0 Brilliant 0 Confused
Itania Ferreira
Jun 28, 2016

And what if i take the time as 60/100 for aqui bullet and as mv/t=force 0,01 .700 /6/10=70/6=35/3

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