Illegal LOGgings

Number Theory Level 2

Evaluate log ⁡ 2 1 × log ⁡ 3 2 × log ⁡ 4 3 × ⋯ log ⁡ 2016 2015 \log_2 1 \times \log_3 2 \times \log_4 3 \times \cdots \log_{2016} 2015 .


The answer is 0.

Ir J by IR J , 21, Philippines

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1 solution

Tommy Li
Aug 22, 2018

Note that log ⁡ 2 1 = 0 \log_{2}{1}=0 , the whole expression is equal to 0

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