I'm back problem - 3 (Is this just mechanics?)

Calculus Level 5

A ball is thrown from the edge of a cliff 50 m 50\: m high, at an angle of 3 0 30^\circ upward from the horizontal and at a speed of 10 m/s 10\text{ m/s} . Refer to (2) in the figure. Neglecting air friction and other external factors, determine the length A A of the path traveled by the ball (depicted in blue dashed lines). Express your answer as A \lfloor A \rfloor .


The answer is 65.

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1 solution

Efren Medallo
Oct 22, 2015

The general equation for a parabolic path is

y = x t a n θ g 2 v 2 c o s 2 θ x 2 \large y = x\:tan \:\theta - \frac{g}{2v^{2}\:cos^{2}\:\theta }\:x^{2}

So, we only have to find the horizontal range of the travel, which is given by

x 0 = v c o s θ ( v g s i n θ + v 2 s i n 2 θ g 2 + 100 g ) \large x_{0} = v\:cos \:\theta\cdot (\frac{v}{g}sin\:\theta + \sqrt{\frac{v^{2}\:sin^{2}\:\theta}{g^2}\: + \: \frac{100}{g}})

Then, this will be the upper limit of the length of the travel path, which is given by

A = 0 x 0 1 + ( y ) 2 d x A = \large \int_0^{x_{0}} \sqrt {1 + (y')^{2} } \: dx

where A 65.4945 A \approx 65.4945 , so A = 65 \lfloor\: A \: \rfloor = \boxed{65}

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