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$ABC$ is a right triangle angle $A=63^\circ$ , angle $B=27^\circ$ . $ACFG$ and $BCDE$ are squares drawn external to the triangle $ABC$ such that $AE$ intersect $BC$ at $h$ and $BG$ intersect $AC$ at $K$ . Then find $\angle DKH$ .

Clarifications: All angles in terms of degrees.