Imaginary roots (1)

1. On the complex plane the roots of a number - whether real or complex - are always evenly spaced apart, meaning all the roots sum to $0$ . This makes it so we can express this question as an equation.

$x_{1} + x_{2} + x_{3} = 0$

1. We know $x_{1} = y$ from the question so we can substitute that in.

$y + x_{2} + x_{3} = 0$

1. We then re-arrange to find the sum.

$\boxed{x_{2} + x_{3} = -y}$

this is too simple . cube both sides use identity a^3-b^3=0 where a=x and b=cube root of n u shall get (x = \sqrt[3]{n}) or the other equation applying vieta answer is -y