ln ( i i ) = k × π
Submit the value of k .
Notation: i = − 1 denotes the imaginary unit .
(Consider the principal branch of the complex logarithm).
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Have you used e i θ = cos θ + i sin θ ? ... Plugging θ = 2 π , e 2 i π = I
why level 4 , it is very very easy ! no offence , they just giving rating to anything ! at most level 2 !
Dont worry about the level bro, it will automatically change as the number of people answer it. Next time please comment it under the solution, currently you have posted it as a solution. Thanks!
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oh ! sorry and thanks for telling ! :) i'll edit it sometime later !
no no you shut up, he's right.
i i ⟹ ln ( i i ) = − 2 π ⟹ k = − 0 . 5 = ( e i × 2 π ) i = e − 2 π
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Relevant wiki: Euler's Formula
ln ( i i ) = i ln i = i ln ( e 2 π i ) = i ( 2 π i ) = − 2 π By Euler’s formula: e 2 π i = cos 2 π + i sin 2 π
⟹ k = − 0 . 5