Impedance of a DC circuit

What is the impedance (in Ω \Omega ) of a series DC circuit with impedance L = 4 H L = 4 \text{H} and resistance R = 3 Ω ? R = 3 \Omega?

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1 solution

Assuming the inductor and the resistor are connected in series, the effective impedance would be the sum of the respective impedances of the resistor and the inductor. At DC (0 Hz), the inductor has zero impedance (Z = j 2 pi f L). Thus, the effective impedance is simply the impedance of the resistor, which would be its resistance, 3 Ohms.

Note that if the inductor and the resistor were connected in parallel, the answer would be 0 Ohms.

Thanks! I updated the problem's wording to indicate they are connected in parallel.

July Thomas - 4 years, 11 months ago

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