Given
where the 3 operators can be and the position of the numbers are free to swap.
Find the sum of all possible odd .
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To get an odd number out of four even numbers, we need to use division
Note:
Therefore, the only possible solution = 4 2 × 4 4 × 4 6 ÷ 4 8 = 7 × 1 1 × 2 3 = 1 7 7 1