Impulse#1

A ball of mass 1 kg is attached to an inextensible string. The ball is released from the position shown in the figure above.

Find the impulse imparted by the string to the ball immediately after the string becomes taut .

If your answer is of the form a b a\sqrt{b} , where a a and b b are positive integers and b b is square - free , then enter the value of a + b a + b .

Note : Take g = 10 m s 2 g = 10~ ms^{-2} .


The answer is 12.

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1 solution

Md Zuhair
Nov 12, 2017

Initially the string, before being taut had momentum 0 0 .

So The Impulse is I = Δ p m v = 1 × 2 2 g I=\Delta p \implies mv = 1 \times \sqrt{2*2*g} 2 10 \implies 2\sqrt{10}

Answer = 2 + 10 = 12 2+10=12 .


I know this problem is done with Impulse of normal and Impulse of Tension and all those, But i didnt used them.

Nicely done , and did the exact same.

Rishu Jaar - 3 years, 7 months ago

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