A number theory problem on bases.

Number $7625$ in base $x=111\space 110\space 010 \space 101$ in base $2$ .

I have divided the number in base $2$ into four groups of three digits each.

If the individual groups are interpreted as numbers in base $2$ , they are $7, 6, 2,$ and $5$

Each triplet is one digit in base $x=2^3=\boxed8$