In equality 2

Algebra Level 4

Let a a , b b , and c c be positive reals so that a b c = 1 abc=1 . The smallest possible value of a 3 ( b + 1 ) ( c + 1 ) + b 3 ( a + 1 ) ( c + 1 ) + c 3 ( a + 1 ) ( b + 1 ) \dfrac{a^3}{(b+1)(c+1)}+\dfrac{b^3}{(a+1)(c+1)}+\dfrac{c^3}{(a+1)(b+1)} can be expressed as A B \frac{A}{B} , where A A and B B are positive integers that are relatively prime. What is A + B A+B ?


The answer is 7.

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