Let be a triangle with incentre . Let be the midpoints of respectively. Let be the circumcentre of triangle . Find the first two decimal places of the length of if .
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Let D, E be the foot of perpendiculars from I to AB, AC. Note that MD = NE = 0.5. Also, ID = IE. So, triangle IDM and triangle IDN are congruent. So, this gives us that A, M, N, I are concyclic. But we also know that A, M, N, X are concyclic where X is the circumcentre of triangle ABC. So, the circumcentre O of triangle MNI is the midpoint of AX. Now the rest is just plain computations.