Increasing Computability

Suppose f : N N f : \mathbb{N} \to \mathbb{N} is a totally computable function which is non-decreasing, that is f ( n ) f ( n + 1 ) f(n) \leq f(n+1) .

When is Range ( f ) \text{Range}(f) computable?

In neither case When Range ( f ) \text{Range}(f) is infinite When Range ( f ) \text{Range}(f) is finite Always

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1 solution

Frisk Dreemurr
Jul 19, 2020

As it never decreases, it can only increase.

Regardless of whether it approaches infinite or not, it is still computable

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