Indefinitely definite!

Calculus Level 1

Which of these is greater? 0 1 2 x 2 d x or 0 1 2 x 3 d x ? \large \int_0^1 2^{x^2}\, dx \text{ or } \int_0^1 2^{x^3}\,dx\quad ?

0 1 2 x 2 d x \int_0^1 2^{x^2}\, dx 0 1 2 x 3 d x \int_0^1 2^{x^3}\, dx Both are equal

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3 solutions

J D
May 10, 2016

Because x 2 x^2 is greater than x 3 x^3 on ( 0 , 1 ) (0,1) , exponentiating both sides means that 2 x 2 2^{x^2} is greater than 2 x 3 2^{x^3} , so there is more area under the curve of 2 x 2 2^{x^2} (integral of 2 x 2 2^{x^2} is greater).

That's really cool!

Kishore S. Shenoy - 5 years, 1 month ago

This was my train of thought too :)

Michael Fuller - 5 years ago
Amarildo Aliaj
Nov 1, 2016

Hana Wehbi
May 11, 2016

evalf(int(2^(x^2),x=0..1));

                         1.288226364

evalf(int(2^(x^3),x=0..1));

                         1.213987326

using Maple.

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