Independence Day!

What day of the week was 15th August 1947 ?

Saturday Friday Monday Thursday Sunday Tuesday Wednesday

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Vineet Singh
Jul 18, 2015

Required Day = Saturday - {(366 * 17 + 365 * 51 - 28)mod7} = Saturday - 1 = Friday

Can you please elaborate the solution?

Simran Kaur - 5 years, 10 months ago

Log in to reply

Simran, I basically found out the remainder of the total number of days between 15 Aug 1947 to 18 July 2015, Saturday (the day when i solved the question) with 7 as there are 7 days in a week.

So, we should see the number of leap years and non leap years between those two dates.

Non leap years is given by [(2015-1947)/4] = 17, while non-leap years are the remaining 51 years.

Also, 15 Aug of any year is 28 days ahead of 18 July. Hence we need to substract 28 from 366 * 17 + 365 * 51.

Since the overall remainder is -1 wrt 7 or a remainder of 6 wrt 7 and we are looking at it with Saturday as the reference (the day when i wrote the solution :-), the required day must have been one less than or 6 more than a Saturday => Friday.

Hope this helps!

Vineet Singh - 5 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...