India's cricket team batman's are tiger in india

Let the number of games played in and out of India be $x$ and $y$ respectively. Then we have:

$\begin{cases} \dfrac 23 x + \dfrac 25 y = 26 & ...(1) \\ x + y = 49 & ...(2) \end{cases}$ $\implies \dfrac 52 \times (1) - (2): \ \dfrac 23 x = 16 \implies x = \boxed{24}$

Let the number of games played in India be $x$ . Then $\dfrac{2x}{3}+\dfrac{2(49-x)}{5}=26$ or $x=\boxed {24}$

Virat's team won at home = $\frac{2}{3}$ of their home games.

Virat's team won away from home = $\frac{2}{5}$ of their away from games.

Virat's team won in total = 26 games out of total 49 games.

$\frac{2}{3}$ of their home games + $\frac{2}{5}$ of their away from games = $\frac{26}{49}$ of their total games.

Now assume total they played games in India are $x$ and total they played games away from India are $y$ .

So $\frac{2x}{3}$ + $\frac{2y}{5}$ = $26$

Now we don't want fractions because we hate fractions and we love whole numbers so multiply both sides by 15.

So 15 *( $\frac{2x}{3}$ + $\frac{2y}{5}$ ) = 15 * 26

= $\frac{15 * 2x}{3}$ + $\frac{15 * 2y}{5}$

= 10x + 6y = 390

= 5x + 3y = 195

And we know that x + y = 49 So 3x + 3y = 147

Now compare this two equations: 3x + 3y = 147 and 5x + 3y = 195

So know subtract (5x + 3y ) - ( 3x + 3y ) = (195 - 147)

= 2x = 48

x = 24

And we have x as no games played in India.

So we know x + y = 49

Then y will be 25.

So matches played in INDIA are x which means "24".

(Optional: Games played far from their home are y which means "25" )