India v Pakistan cricket match

Possibilities and probabilities tossing 4 coins are:

to get 0 heads probability is $\frac1{2^4}$ , for two persons $\frac1{2^4} \cdot \frac1{2^4}=\bf{\frac1{256}}$

to get 1 head is $\frac{{4 \choose 1}}{2^4}$ , for two persons $\frac 4{16}\cdot\frac4{16}=\bf{\frac{16}{256}}$

to get 2 heads is $\frac{{4 \choose 2}}{2^4}$ , for two persons $\frac 6{16}\cdot\frac6{16}=\bf{\frac{36}{256}}$

to get 3 heads is $\frac{{4 \choose 3}}{2^4}$ , for two $\frac4{16}\cdot\frac4{16}=\bf{\frac{16}{256}}$

to get 4 heads is $\frac{1}{2^4}$ , for two $\frac 1{16}\cdot\frac1{16}=\bf{\frac{1}{256}}$

Sum of these probabilities is $\frac{70}{256}=\bf{\frac{35}{128}}$

[4C0 * 1/2^0 * 1/2^4 ]^2

+ [4C1 * 1/2^1 * 1/2^3]^2

+......... +.........+ [4C4 * 1/2^4 * 1/2^0]^2 = 35/128