Indices

$2000(2000^{2000}) = (2000^{1})(2000^{2000}) = 2000^{2001}$

Ha..a simple one indeed..its the 3rd law of indices that if $x^{a} ( x^{b})$ , then it will be $x^{a+b}$ , hence in this $2000^{1+2000}$ = $2000^{2001}$

$a\times({a}^{a})={a}^{1}\times{a}^{a}={a}^{a+1}$ where $a \in \mathbf{Z}$

Put $a=2000$ so you will get the desire result

$2000^1 \times 2000^{2000}=2000^{1+2000}=\boxed{\large{2000^{2001}}}$

$2000(2000^{2000})$ $= 2000^{1 + 2000}$ $= 2000^{2001}$

We can just use the Product Rule for this problem:

$2000(2000^{2000}) = 2000^{2000 + 1} = 2000^{2001}$

2000(2000 2000 )=(2000 1 )(2000 2000 )=2000 2001

laws of exponents

This most easy problem but just 65% people have solved this problem
!!!!!!!!!!!!!!!! Amazing!!!!!!!!!!!!!!!!!

Base same and power add

2000(2000^2000)=(2000^1)(2000^2000) =2000^1+2000 =2000^2001

Lets see how many times we are multiplying 2000, there are 2000times so that is multiplied by one more 2000, there for it's 2001 times being multiplied. The answer is 2000²°°¹

2000(2000^2000) = 2000 x 2000^2000 = 2000^2001

(X^m)(X^n)=X^m+n

2000^1(2000^2000)=2000^2000+1

let 2000 = x; x^1*x^2000=x^2001

im not sure

2000(2000^2000)= 2000^1(2000^2000) =2000^2000+1 = 2000^2001 this is one of the law of exponents