Induced electromotive force

Electricity and Magnetism Level 1

The above diagram is a uniform magnetic field with intensity $4\text{ T}.$ The direction of the magnetic field is downwards through the plane on which a conducting wire and a $20\text{ cm}$ metal stick are placed as shown above. If we drag the metal stick on the conducting wire to the right at a constant speed of $1 \text{ m/s},$ then what is the current intensity flowing in the resistor with a resistance of $2 \text{ }\Omega?$

1.2\text{ A}

0.8\text{ A}

1.0\text{ A}

0.4\text{ A}

2 solutions

Arijit Banerjee
Mar 18, 2014

we know Emf = B L v . emf = 0.8 V from this emf we get current(i) = emf/R = 0.4 A... hence a is correct .. now b is incorrect bcoz if we apply Fleming's Right Hand rule we get current in anti-clockwise direction c is correct we can get it using law of energy consevation

EMV=(u*B).dl all of them under integral sign which will lead to i=.4 A so A is right .for B the induced emf must be oppose the original one according to lenz low but in this state it is in the same direction. for C the concept of energy conservation

Hossam Alfakher - 7 years, 2 months ago

u cud hav posted it as solution

Arijit Banerjee - 7 years, 2 months ago

Exact explaination!!!!

Badrinath Mamandur - 7 years, 2 months ago

@Arijit Banerjee Please explain the formula you used-"EMF=BLv"

Anurag Bisht - 3 years, 8 months ago

You can find this formula or rather concept in any 12 standard physics book of any author. https://www.physicsforums.com/threads/proving-v-blv.612738/

Arijit Banerjee - 3 years, 8 months ago

Ok. Thanks a lot.

Anurag Bisht - 3 years, 8 months ago

Hossam Alfakher
Mar 21, 2014

Induced electromotive force

2 solutions

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