Inductor + Capacitors

Two capacitors of capacitances C 1 C_1 and C 2 C_2 are connected in series with an inductor of inductance L L . Initially the capacitors have charge such that V B V A = 4 V 0 V_B-V_A=4V_0 across C 1 C_1 and V C V D = V 0 V_C-V_D=V_0 across C 2 C_2 . Now if

a) Maximum current in circuit is ξ \xi .

b) Potential drop across C 1 C_1 is μ \mu at that instant.

c) Potential drop across C 2 C_2 is η \eta at that instant.

d) Equation of current flowing towards left in the inductor is given by i = ψ ( sin ( ω t ς ) ) i= \psi \left( \sin { \left( \frac { \omega t }{ \varsigma } \right) } \right) .

Find ξ + μ + η + ψ + ω + ς \xi +\mu +\eta +\psi +\omega +\varsigma .

Details And Assumptions:

  • C 0 = 2 F C_0=2F

  • L = 1 3 H L=\dfrac 13 \ H

  • V 0 = 4 volt V_0=4 \ \text{volt}

  • Initially the current in the circuit is zero.

  • ω \omega and ς \varsigma are co-prime.


The answer is 77.

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