Inequality (1)

Algebra Level 3

Let a , b , c , d a,b,c,d be real numbers such that a 2 + b 2 + c 2 + d 2 = 4 , a^2+b^2+c^2+d^2=4, then a 3 + b 3 + c 3 + d 3 n , a^3+b^3+c^3+d^3\le n, where n > 0. n>0.

What is the value of n ? n?


The answer is 8.

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1 solution

Jon Haussmann
Mar 5, 2018

Note that a 2 a 2 + b 2 + c 2 + d 2 4 a^2 \le a^2 + b^2 + c^2 + d^2 \le 4 , so a 2 a \le 2 . Hence, ( 2 a ) a 2 0 , (2 - a)a^2 \ge 0, or a 3 2 a 2 a^3 \le 2a^2 . Similarly, b 3 2 b 2 b^3 \le 2b^2 , c 3 2 c 2 c^3 \le 2c^2 , and d 3 2 d 2 d^3 \le 2d^2 . Adding these up, we get a 3 + b 3 + c 3 + d 3 2 ( a 2 + b 2 + c 2 + d 2 ) = 8. a^3 + b^3 + c^3 + d^3 \le 2(a^2 + b^2 + c^2 + d^2) = 8. Equality occurs when one of a a , b b , c c , d d is equal to 2, and the other three are equal to 0.

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