Let be real numbers such that then where
What is the value of
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Note that a 2 ≤ a 2 + b 2 + c 2 + d 2 ≤ 4 , so a ≤ 2 . Hence, ( 2 − a ) a 2 ≥ 0 , or a 3 ≤ 2 a 2 . Similarly, b 3 ≤ 2 b 2 , c 3 ≤ 2 c 2 , and d 3 ≤ 2 d 2 . Adding these up, we get a 3 + b 3 + c 3 + d 3 ≤ 2 ( a 2 + b 2 + c 2 + d 2 ) = 8 . Equality occurs when one of a , b , c , d is equal to 2, and the other three are equal to 0.