Inequality without Solution

Algebra Level 2

What is the sum of the value of b b and the maximum value of a a such that the inequality 16 x a < b x + 9 16x-a<bx+9 does not have a solution?

7 7 9 9 6 6 8 8

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2 solutions

Ipsit Chopra
Mar 30, 2014

Its a bit unclear problem but still it has a reasonable solution we can write the inequality as x < (a+9)/(16 -b) hence b=16 is the point at which the fraction becomes undefined. also if a= -9, the inequality becomes 16 x < b x which implies b >16. but b=16 hence the answer is 16-9=7

nice solution

shweta dalal - 6 years, 3 months ago
Filippo Olivetti
Nov 24, 2016

We can write the inequality as: ( 16 b ) x < a + 9 (16-b)x < a+9 Now we see that 16 b = 0 16-b = 0 because if ( 16 b ) ( x + 1 ) > ( 16 b ) x |(16-b)(x+1)| > |(16-b)x| , there's no limit for the value of the first member of the inequality and a a cannot be determined. Hence, b = 16 , a + 9 = 0 a = 9 b = 16, a+9=0 \rightarrow a=-9

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