Infinite exponentials

Level pending

The field of infinite fractions and exponentials is incredibly interesting. Give this problem a shot:

x x x . . . = n x^{x^{x^{...}}} = n

What is x x ?

n 1 / n n^{1/n} n n n\sqrt{n} n 0 1 n 1 / 2 n^{1/2}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Imran Qureshi
Mar 28, 2016

The problem looks nigh impossible if you try to keep thinking of numbers that would equal n if kept "exponentiating it". Instead let's think of the problem in a more clever way, consider it without the leading x on the left side, what do we have left?

x x . . . = n x^{x^{...}} = n

Well that's pretty much the same as our previous equation, so let's plug that into our original problem:

x n = n x^{n} = n

Now its incredibly easy, just take the nth root of both sides - netting you x = n 1 / n x = n^{1/n} which is our answer.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...