Consider the following fraction:
1 0 1 + 1 0 2 + 1 0 3 + 1 0 1 + 1 0 2 + 1 0 3 + ⋰
The fraction can be formalized via recursive definition as a where a = 1 0 1 + b and b = 1 0 2 + c and c = 1 0 3 + a
a is a rational number and has a reduced fraction form X / Y where X and Y are positive integers. What is 3 X + 3 Y ?
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It should be a= (1+b)/10 in the question, similarly with b and c
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(very informal solution)
a = 1 0 1 + 1 0 2 + 1 0 3 + a
a = 1 0 0 0 1 2 3 + a
a = 0 . 1 2 3 1 2 3 1 2 3 . . .
a = 1 2 3 / 9 9 9 = 4 1 / 3 3 3
X = 4 1
Y = 3 3 3
3 X + 3 Y = 1 2 3 + 9 9 9 = 1 1 2 2